10th Class Physical Sciences – 4 and 2 Marks Important Questions

Question: What is the action of soap particles on greasy cloth? (4 Marks)

Answer: Soaps and detergents make oil and dirt present on the cloth come out into water, there by making the cloth clean.
a) Soap has one polar end and one non-polar end.
b) The polar end is hydrophilic in nature and this end is attracted towards water.
c) The non-polar end is hydrophobic, in nature and it is attracted towards grease or oil on the cloth, but not attracted towards water.
d) When soap is dissolved in water, its hydrophobic ends attach themselves to dirt and remove it from the cloth.
e) The hydrophobic end of the soap molecules move towards the dirt or grease particles.
f) The hydrophobic ends attached to the dirt particle and try to pull out.
g) The molecules of soap surround the dirt particle at the centre of the cluster and form a spherical structure called micelle.
h) These micelles remain suspended in water like particles in a collidal solution.
i) The various micelles present in water do not come together to form a precipitate as each micelle repells the other because of the ion- ion- repulsion.
j) Thus, the dust particles remain trapped in micelles and are easily rinsed away with water.
k) Hence, soap micelles remove dirt by dissolving in water.

Question:

We know metals are arranged basing on their reactivity. What is the name given to that arrangement? How it helps in extraction of metals? (4 Marks)

Answer: Activity Series: Extraction of the metal from its ore depends on the reactivity of the metal.
a) To understand the order of reactivity of metals that are very familiar, we study their chemical reactions with cold water, steam, dilute, strong acids and Cl2 and based on their vigorous activity order in these reactions, we frame out activity series.
b) Arrangement of the metals in decreasing order of their reactivity is known as activity series. Usefulness of activity series in extraction of metals:
c) Simple chemical reduction methods like heating with C, Co etc., to reduce the ores of these metals depends mainly on the position of the metal in the activity series.
d) Extration of metals at the top of the activity series can be done by electrolysis.
e) Extraction of metals in the middle of the activity series can be extracted by
1)) Sulphide ores are converted into oxides by roasting.
2) The metal oxides are then reduced to the corresponding metal by using suitable reducing agents like carbon.
f) Extraction of metals at the bottom of the acitivity series by heating alone as they are often found in free state.
g) Extraction of these metals can also be done by displacement from aqueous solutions.

Question:

How do you appreciate the role of Buckminister fullerence in medicine. (2 Marks)

Answer: Fullerences are under study for potential medicinal use such as specific antibiotics to target resistant bacteria and even target certain cancer cells such as melonoma.
a) This is still under research studies.
b) I appreciate its usefulness in medicine which may become a good medicine for curing certain cancer in the time to come.

Question:

What is the role of esters in everyday life? (2 Marks)

Answer: Esters are generally volatile liquids with sweet or pleasent smell or fruity smell.
a) Artificial perfumes are made with esters.
b) Esters are used as flavouring agents.
c) Esters are used in making artificial flavours and essences used in ice-creams, sweets, cool drinks… etc.,
d) Saponification (soap making) is the alkaline hydrolysis of esters.

10th Class Physical Sciences Bit Bank – Fill in the Blanks

101. Na, K etc., were obtained from ……….
102. The second period consists ……. s-block elements and ……. p-block elements.
103. There are ……. elements in the sixth period.
104. ‘4f’ elements are called ………
105. ‘5f’ elements are called ……….
106. The elements with three or less electrons in the outer shell are considered to be ……….
107. Lanthanoids and actinoids are called ……. elements.
108. Metalloids are generally ……….
109. Atomic radius is measured in ……….
110. 1 pico metre = ………. meter.

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111. Atomic radii of elements ……… across a period from left to right.
112. Atomic radii ……… from top to bottom is a group of the periodic table.
113. The size of the chlorine atom is ……… than Cl- ion.
114. The size of Na+ ion is ………. than ‘Na’ atom.
115. The energy required to remove an electron from the outer most orbit or shell of a neutral gaseous atom is called ……….
116. The energy required to remove an electron from unipositive ion of the element is called the ……… of that element.
117. More the nuclear charge ……. is the ionization energy.
118. More the screening effect ……… is the ionization energy.
119. It is …….. to remove 4f electron than 4s.
120. It is …….. to remove one electron from 8O than 7N.
121. More the atomic radius, ……… is the ionization energy.
122. Ionization energy is expressed in ………
123. Electron affinity of an element is also called electron gain ………… of that
element.
124. Electron affinity value for Chlorine is ……..
125. Metals have very …….. electron gain enthalpy values. Ionization energy + ………….
126. Electronegativity = Ionization energy + ………… / 2
127. ……….. assigned the electronegative values for elements on the basis of bond
energies.
128. Metals generally show ……….. electronegative character.
129. Non metals are generally ………. electronegative due to their smaller atomic
radii.
130. Si and Ge are …………

Answers:

101) Plant ash 102) 2, 6
103) 32 104) Lanthanides
105) actinides 106) metals
107) inner transition 108) semi conductors
109) pm (pico meter) 110) 10-12
111) decrease 112) increase
113) less size 114) less
115) ionization energy 116) 2nd ionization energy
117) more 118) less
119) easier 120) easier
121) less 122) kJ mol-1
123) enthalpy 124) -349 kJ mol-1
125) low 126) electron affinity
127) Pauling 128) less
129) more 130) metalloids

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